36=(1/25)x^2

Solution for 36=(1/25)x^2 equation:

36=(1/25)x^2

We move all terms to the left:

36-((1/25)x^2)=0


Domain of the equation: 25)x^2)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-((+1/25)x^2)+36=0

We multiply all the terms by the denominator


-((+1+36*25)x^2)=0


We calculate terms in parentheses: -((+1+36*25)x^2), so:

(+1+36*25)x^2

We add all the numbers together, and all the variables

901x^2

Back to the equation:

-(901x^2)


a = -901; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-901)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-1802}=0$